1.

6.24 g of ethanol are vaporized by supplying 5.89 kJ of heat energy. What is enthalpy of vaporization of ethanol?

Answer»

Given : 

Mass of ethanol (C2H5OH) = m = 6.24 g 

Heat energy supplied = ΔH = 5.89 kJ

Heat of vaporisation of ethanol = ΔvapH = ?

Molar mass of ethanol,

C2H5OH = 46 g mol-1

∵ For 6.24 g C2H5OH  ΔH = 5.89kJ

∴ For 1 mole C2H5OH = 46 g C2H5OH

ΔH = \(\frac{5.89\times 46}{6.24}\)

= 43.42 kJ mol-1

∴ Enthalpy of vaporisation of C2H5OH(I)

= 43.42 kJ

∴ Enthalpy of vaporisation of C2H5OH(I)

= 43.42 kJ



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