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6.24 g of ethanol are vaporized by supplying 5.89 kJ of heat energy. What is enthalpy of vaporization of ethanol? |
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Answer» Given : Mass of ethanol (C2H5OH) = m = 6.24 g Heat energy supplied = ΔH = 5.89 kJ Heat of vaporisation of ethanol = ΔvapH = ? Molar mass of ethanol, C2H5OH = 46 g mol-1 ∵ For 6.24 g C2H5OH ΔH = 5.89kJ ∴ For 1 mole C2H5OH = 46 g C2H5OH ΔH = \(\frac{5.89\times 46}{6.24}\) = 43.42 kJ mol-1 ∴ Enthalpy of vaporisation of C2H5OH(I) = 43.42 kJ ∴ Enthalpy of vaporisation of C2H5OH(I) = 43.42 kJ |
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