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6.A natural number is greater than the other by5. The sum of their squares is 73. Find thenumbers. |
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Answer» let the no. is x andx+5 x²+(x+5)²=73 let first number=x other number=x+5 according to question,(x²)+(x+5)²=73x²+x²+25+10x=732x²+10x+25-73=02x²+10x-48=0dividing by 2,x²+5x-24=0x²+8x-3x-24=0x(x+8)-3(x+8)=0(x+8)(x-3)=0x-3=0x=3first number=3other number=3+5=8 ans. |
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