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6. Find the speed of a train which leaves Secundrabad at 7 p.m. and reaches Bhopal the nextday at 6 a.m. It stops for I hour on the way. The distance between Secundrabad and Bhopalis 710km. Also, find the average speed correct to one place of decimal.

Answer»

Distance travelled = 710 kmTime taken = 10 hrs

We know Distance = speed * time Speed = Distance /time = 710/10 = 71 km/hr

Average speed = 71 km/hr

average speed



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