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\(6-\frac{x-1}{2}= \frac{x-2}{3}+\frac{3-x}{4}\, \) x = ......................6 - x - 1/2 = x - 2/3 + 3 - x/4 x = .........................A) 11 B) 10 C) – 6 D) – 4 |
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Answer» Correct option is A) 11 Correct option is (A) 11 \(6-\frac{x-1}{2}=\frac{x-2}{3}+\frac{3-x}{4}\) \(\Rightarrow\) \(\frac{x-2}{3}+\frac{3-x}{4}+\frac{x-1}{2}=6\) \(\Rightarrow\) \(\frac{4(x-2)+3(3-x)+6(x-1)}{12}=6\) \(\Rightarrow\) 4x-8+9-3x+6x-6 = 72 \(\Rightarrow\) 7x - 5 = 72 \(\Rightarrow\) 7x = 72+5 = 77 \(\Rightarrow\) x = \(\frac{77}7\) = 11. |
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