6 g of carbon combines with 32 g of sulphur toform CS2. 12 g of C also

1.	6 g of carbon combines with 32 g of sulphur toform CS2. 12 g of C also combine with 32 g ofoxygen to form carbon dioxide. 10 g of sulphurcombines with 10 g of oxygen to form sulphurdioxide. Which law is illustrated by them?
Answer» Law of Reciprocal Proportions is illustrated here. The amount of Sulphur and Oxygen that react with 6 g of carbon are in ratio 32:16= 2:1 Similarly, the other two ratio can be expressed in terms of whole numbers.

6 g of carbon combines with 32 g of sulphur toform CS2. 12 g of C also combine with 32 g ofoxygen to form carbon dioxide. 10 g of sulphurcombines with 10 g of oxygen to form sulphurdioxide. Which law is illustrated by them?

Answer»

Law of Reciprocal Proportions is illustrated here.

The amount of Sulphur and Oxygen that react with 6 g of carbon are in ratio 32:16= 2:1

Similarly, the other two ratio can be expressed in terms of whole numbers.