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6. In a two digit number, the ten's digit is three times the unit's digit when the number is increasedby 54, the digits are reversed, find the number. |
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Answer» Let the digit at unit's place be x.GIVEN : digit at Ten’s place = 3xNumber formed :10 × 3x + x = 30x + x = 31xNumber formed after reversing the digits: 10 × x + 3(x )= 10x +3x = 13xATQ,31x -54 = 13x [Given]31x -13x = 5418x = 54x = 54/18x= 3Number = 31x = 31 × 3 = 93 Hence, the number is 93. |
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