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6. In the adjoining figure, O is the centre of circle anddiameter AC = 26 cm. If chordAB = 10 cm, then the distancebetween chord AB and centre o of thecircle is:(a) 24 cm(b) 16 cm(c) 12 cm(d) none of the above

Answer»

AC=26cmthereforeradius AO=1/2AC=1/2x26=13cmNow AB=10 cmsince distance from centre of circle to a chord bisect the chord therefore AM=1/2AB=1/2x10=5cmIn right ΔAMO using pythagoras theorem we getAO²=AM²+OM²13²=5²+OM²OM²=169-25OM²=144OM²=12²OM=12cmtherfore correct option is (c) 12cm

OA^2= OM^2+AM^2(13)^2= OM^2+(5)^2169-25=OM^2√144= OM12 CM= OMdist from center is 12cm

option c is the right answer

option c is the right answer

option c is the correct answer



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