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6. Show that the points P,3), (6, - 2) and R(-3, 4) are collinear. |
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Answer» p=(-3/2,3), q=(6,-2), R=(-3,4) y 3 points. Y=1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]=0; 1/2[-3/2(-2-4)+6(4-3)+(-3)[3+2]=0;. 1/2[-3/2(-6)+6(1)-3(5)=0; 1/2[9+6-15]=1/2[15-15]=0; if the slope of PQ=QR=PR then the points lie in a same plane or are collinear |
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