(6) The equation 5x2 -26x+ p 0 has reciprocal roots. Findp.quation 5x2

1.	(6) The equation 5x2 -26x+ p 0 has reciprocal roots. Findp.quation 5x2 -26x+ p-0 has reciprocal roots. Find p.
Answer» = Let the roots be a and 1/a.= Sum of roots = -b/a= a + 1/a = 26 / 5 = 5 a^2 + 5 = 26 a = 5 a^2 - 26 a + 5 = 0 Solve for a and substitute in place of x to get the value of p./ here one root is a then another root is 1\a so there product is 1=p/5 so p =5

(6) The equation 5x2 -26x+ p 0 has reciprocal roots. Findp.quation 5x2 -26x+ p-0 has reciprocal roots. Find p.

Answer»

= Let the roots be a and 1/a.= Sum of roots = -b/a= a + 1/a = 26 / 5

= 5 a^2 + 5 = 26 a

= 5 a^2 - 26 a + 5 = 0

Solve for a and substitute in place of x to get the value of p./

here one root is a then another root is 1\a so there product is 1=p/5 so p =5