60 gm of oleum (labelled as 118%) is mixed with 11.8 gm of water. What will be the composition of final mixture?

60 gm of oleum (labelled as 118%) is mixed with 11.8 gm of water. What

1.	60 gm of oleum (labelled as 118%) is mixed with 11.8 gm of water. What will be the composition of final mixture?
Answer» <html><body><p>Only `H_(2)SO_(4)`, having <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> 71.8 gm<br/>118 gm of `H_(2)SO_(4)`<br/>70.8 gm `H_(2)SO_(4)` and <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> gm water <br/><a href="https://interviewquestions.tuteehub.com/tag/32-307188" style="font-weight:bold;" target="_blank" title="Click to know more about 32">32</a> gm `SO_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` and 39.8 gm `H_(2)SO_(4)`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>