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60 students of Section A of Class XI, obtained 40 mean marks in Statistics, 40 students of Section B obtained 35 mean marks in Statistics. Find out mean marks in Statistics for Class XI as a whole. |
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Answer» SOLUTION :Given: `N_(1)=60,barX_(1)=40,N_(2)=40,barX_(2)=35` `"We know, "barX_(12)=(barX_(1)N_(1)+barX_(2)N_(2))/(N_(1)+N_(2))` `:.""barX_(12)=(40xx60+35xx40)/(60+40)` `:.""barX_(12)=(2,400+1,400)/100=(3,800)/100=38` THUS, Combinaed Arithmetic Mean = 38. |
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