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`60g` of compound on analysis gave `C = 24g, H= 4 g` and `O = 32g`. If Empirical formula isA. `C_(2)H_(4)O_(2)`B. `C_(2)H_(2)O`C. `CH_(2)O_(2)`D. `CH_(2)O` |
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Answer» Correct Answer - D `{:("Element"," NO. of moles"," Simple ratio"),(C =24,24//12=2,1),(H=4,4//1=4,2),(O=32,32//16,1):}` Therefore `CH_(2)O`. |
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