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If `0.228 g` of silver salt of dibasic acidgave a residue of `0.162 g` of silver of ignition then molecular weight of the acid isA. 70B. 80C. 90D. 100 |
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Answer» Correct Answer - C Mass of silver salt taken `= 0.228 gm` Mass of silver left `= 0.162gm` Basicity of acid `= 2` Step 1 : To calculate the equivalent mass of the silver salt (E ). `(" Eq.mass of silver salt")/(" Eq. mass of silver ") = (" Mass of acid taken ")/(" Mass of silver left ")` `= E/ 108 = (0.0228)/(0.162)` `= E = (0.228)/(0.162) xx 108 = 152` (Eq. mass of silver salt) Step 2. to calculate the eq. mass of acid . Eq. mass of acid = Eq. mass of silver salt - Eq. mass of Ag + Basicity `= 152- 108 +1 = 152 - 107 = 45` (Eq. mass of acid) Step 3 : To determine the molecular mass of acid. Mol. mass of the acid = Eq. mass of acid `xx` basicity `= 45 xx 2 = 90`. |
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