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`62.5 XX 10^(18)` electorns per second are flowing through a wire of area of cross-section `0.1 m^(2)`, the value of current flowing will beA. `1 A`B. `0.1 A`C. `10 A`D. `0.11 A` |
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Answer» Correct Answer - C (c ) `i= (n e)/(t) = (62.5 xx 10^(18) xx 1.6 xx 10^(-19))/(1) = 10` ampere |
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