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63. If (a + i b)-yF, then the value1+i1-i(a2 +b2) is1S |
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Answer» a+ib=√1+i/1-ia+ib=√1+i/1-i*(1+i)/(1-i)a+ib=1+i/√2hence now a-ib=1-i/√2now a^2+b^2=(a-ib)(a+ib)=2/2=1 |
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