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632 g of sodium thiosulphate (Na_2S_2O_3) reacts with copper sulphate to form cupric thiosulphate which is reduced sodium thiosulphate to give cupros compound which is dissolved in excess of sodium thiosulphate to form a complex compound sodium cuprothiosulphate (Na_4[Cu_6(S_2O_3)_5]). CuSO_4+Na_2S_2O_3toCuS_2O_3+Na_2SO_4 2CuS_2O_3+Na_2S_2O_3toCu_2S_2O_3+Na_2S_4O_6 3Cu_2S_2O_3+2Na_2S_2O_3to underset("Sodium cuprothiosulphate")(Na_4[Cu_6(S_2O_3)_5]) In this process, 0.2 moles of sodium cuprothiosulphate is formed. (O=16, Na=23, S=32) The average oxidation states of sulphur in Na_2S_2O_3 and Na_2S_4O_6 are respectively. |
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Answer» `+5 & +2` `2+2x+3(-2)=0` or 2x=6-2 or 2x=4 x=+2 Suppose oxidation number of sulphur in `Na_2S_4O_6`is y 2+4Y+3(-2)=0 or 4y =12-2 or 4y=10 y=+2.5 |
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