1.

632 g of sodium thiosulphate (Na_2S_2O_3) reacts with copper sulphate to form cupric thiosulphate which is reduced sodium thiosulphate to give cupros compound which is dissolved in excess of sodium thiosulphate to form a complex compound sodium cuprothiosulphate (Na_4[Cu_6(S_2O_3)_5]). CuSO_4+Na_2S_2O_3toCuS_2O_3+Na_2SO_4 2CuS_2O_3+Na_2S_2O_3toCu_2S_2O_3+Na_2S_4O_6 3Cu_2S_2O_3+2Na_2S_2O_3to underset("Sodium cuprothiosulphate")(Na_4[Cu_6(S_2O_3)_5]) In this process, 0.2 moles of sodium cuprothiosulphate is formed. (O=16, Na=23, S=32) The average oxidation states of sulphur in Na_2S_2O_3 and Na_2S_4O_6 are respectively.

Answer»

`+5 & +2`
`+2 & +2.5`
`+5 & 2.5`
`+2 & +4`

Solution :Suppose OXIDATION NUMBER of sulphur in `Na_2S_2O_3` is x
`2+2x+3(-2)=0`
or 2x=6-2
or 2x=4
x=+2
Suppose oxidation number of sulphur in `Na_2S_4O_6`is y
2+4Y+3(-2)=0
or 4y =12-2
or 4y=10
y=+2.5


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