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.^(64)Cu (hlaf lifre = 12.8h)deacays by beta^(-) emission (38%), beta^(+)- emission (19%) and electron capute (43%). Write the decay products and calculatepartial half-live for each of the decay processes. |
Answer» Solution :We know, Given `lambda_(av) = (0.693)/(12.8) hr^(-1)` `:. lambda_(1) +lambda_(2) +lambda_(3) =lambda_(av) = (0.693)/(12.8) = 5.41xx10^(-2) hr^(-1)` .....(1) ALSO for parallel PATH DECAY `lambda_(1)` = Fractionlal yield of `._(30)^(64)Zn xx lambda_(av)` `lambda_(2)` = Fractionalyeild of `._(28)^(64) Ni xx lambda_(av)` `lambda_(3)` = Fractionlal yield of `._(28)^(64) Ni xx lambda_(av)` `:. (lambda_(1))/(lambda_(2)) = (38)/(19)` ....(2) `(lambda_(1))/(lambda_(3)) = (38)/(43)` ....(3) From eqs. (1), (2) and (3) `lambda_(1) = 2.056xx10^(-2) hr^(-1)` `lambda_(2) = 1.028xx10^(-2) hr^(-1)` `lambda_(3) = 2.327xx10^(-2) hr^(-1)` `:. t_(1//2)` for `beta^(-)` emission `= (0.693)/(2.056xx10^(-2)) = 33.70 hr` `t_(1//2)` for `beta^(+)` emission `= (0.693)/(1.028xx10^(-2)) = 67.41 hr` `t_(1//2)` for electron capture `= (0.693)/(2.327xx10^(-2)) = 29.28 hr` |
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