65) Consider the set A = {1,2,3,..., 30). The number of ways in which

1.	65) Consider the set A = {1,2,3,..., 30). The number of ways in which one can choose threedistinct numbers from A so that the product of the chosen numbers is divisible by isA) 1590B) 1505C) 1110D) 1025
Answer» 1505 is the best answer 1505 is the correct answer me There are 10 numbers divisible by 3 viz. 3, 6, 9, 12 ... 30. Case I : we have 2 of these 10 and one from remaining 20 10C2 X 20C1 = 900 Case II: we have all 3 numbers coming from these 10 10C3 = 120 Case III: Out of these 10, - (9, 18 and 27) are divisible by 9. We take only 1 number from these 3 and other 2 come from remaining 20 3c1 X 20C2 = 570 Total 900 + 120 + 570 = 1590 hence A is correct answer 1505 is my answer 😘😘😘 how minny pisos did lebch get 1505 is right answer you question

65) Consider the set A = {1,2,3,..., 30). The number of ways in which one can choose threedistinct numbers from A so that the product of the chosen numbers is divisible by isA) 1590B) 1505C) 1110D) 1025

Answer»

1505 is the best answer

1505 is the correct answer me

There are 10 numbers divisible by 3 viz. 3, 6, 9, 12 ... 30. Case I : we have 2 of these 10 and one from remaining 20 10C2 X 20C1 = 900 Case II: we have all 3 numbers coming from these 10 10C3 = 120 Case III: Out of these 10, - (9, 18 and 27) are divisible by 9. We take only 1 number from these 3 and other 2 come from remaining 20 3c1 X 20C2 = 570 Total 900 + 120 + 570 = 1590 hence A is correct answer

1505 is my answer 😘😘😘

how minny pisos did lebch get

1505 is right answer you question

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