7.45 grams of KCL s dissolved in 100 grams of water.whaat will be the

1.	7.45 grams of KCL s dissolved in 100 grams of water.whaat will be the molality of the solution
Answer» Answer: 1 MOLE/kg. Explanation: Molality is DEFINED as the number of moles of SOLUTE present in 1kg of solvent. and is denoted by m. Thus, molality(m) = No. of moles of solute / Mass of solvent. Here, solute is 7.45 grams of KCl and solvent is 100 grams of water = 0.1 kg GMW of KCl= 39+35.5=74.5g Moles of KCl: 74.5 g of KCl = 1 mole (for any weight) then, 7.45 g of KCl = X moles x =7.45 x 1/74.5 x=0.1 mole. So, molality(m) = No. of moles of solute / Mass of solvent molality= 0.1/0.1 = 1 mole/kg. (Remember that the numerator PART of the formula is moles and not mass) Hope it helps:) All the best!!!

7.45 grams of KCL s dissolved in 100 grams of water.whaat will be the molality of the solution

Answer»

Answer:

1 MOLE/kg.

Explanation:

Molality is DEFINED as the number of moles of SOLUTE present in 1kg of solvent.

and is denoted by m.

Thus, molality(m) = No. of moles of solute / Mass of solvent.

Here, solute is 7.45 grams of KCl and solvent is 100 grams of water = 0.1 kg

GMW of KCl= 39+35.5=74.5g

Moles of KCl:

74.5 g of KCl = 1 mole (for any weight)

then, 7.45 g of KCl = X moles

x =7.45 x 1/74.5

x=0.1 mole.

So, molality(m) = No. of moles of solute / Mass of solvent

molality= 0.1/0.1

= 1 mole/kg.

(Remember that the numerator PART of the formula is moles and not mass)

Hope it helps:)

All the best!!!