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7.An elevator descends into a mine shaft at the rate of 6 m/min. If the descen7ke orach-350m.

Answer»

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,

The elevator has to travel 10m till the ground, then 350 m more.

So, the total distance to travel is 360 m

If the elevator's speed is 6 metres/minute,Then

Time= Distance/Speed = 360/6 =60 minutes =1 hour

Thus the elevator would take 1 hour to reach its destination.



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