7. Find the area of the given figure.+20 cm20 cm -15 cm-16 cm-30 cm

1.	7. Find the area of the given figure.+20 cm20 cm -15 cm-16 cm-30 cm
Answer» Here, area of the given figure will be:Area of two trapeziums + area of 1 trapezium + area of rectangle First, height(h) of both trapeziums will be 30cm. - 16cm. = 14cm. Now, height(h) of each trapezium = 14/2 = 7cm. Now, area of both trapeziums = 2 × h(a + b)/2 [Where a and b are parallel sides of the trapeziums] = h(a + b)= 7cm.(20 + 5)cm.= 7cm. × 25cm.= 175cm² Similarly, area of another trapezium = 4cm.(16 + 30)cm.= 4cm. × 46cm.= 184cm² Now, area of rectangle = l × b5cm. × 16cm. = 80cm² Now, adding all the areas, we get439cm² Thus, area of the given figure = 439cm²

Answer»

Here, area of the given figure will be:Area of two trapeziums + area of 1 trapezium + area of rectangle

First, height(h) of both trapeziums will be 30cm. - 16cm. = 14cm.

Now, height(h) of each trapezium = 14/2 = 7cm.

Now, area of both trapeziums = 2 × h(a + b)/2

[Where a and b are parallel sides of the trapeziums]

= h(a + b)= 7cm.(20 + 5)cm.= 7cm. × 25cm.= 175cm²

Similarly, area of another trapezium = 4cm.(16 + 30)cm.= 4cm. × 46cm.= 184cm²

Now, area of rectangle = l × b5cm. × 16cm. = 80cm²

Now, adding all the areas, we get439cm²

Thus, area of the given figure = 439cm²

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