7/ Given that the equilibrium constant for the re2502(g) + O2(g)-2503(

1.	7/ Given that the equilibrium constant for the re2502(g) + O2(g)-2503(g). has a value278 at a particular temperature. What is the vabueof the equilbirum constant for the following reactionat the same temperature?SO,(g)SO.(9)+ 29)[AIPMT (Mains)-2012
Answer» when the reaction is reversed , the equilibrium constant becomes reciprocal of the actual reaction and when its coefficients are halved it gets 1/2 power on it so, for the reaction shown below the equilibrium constant will be (1/k)^(1/2)= 1/√278

7/ Given that the equilibrium constant for the re2502(g) + O2(g)-2503(g). has a value278 at a particular temperature. What is the vabueof the equilbirum constant for the following reactionat the same temperature?SO,(g)SO.(9)+ 29)[AIPMT (Mains)-2012

Answer»

when the reaction is reversed , the equilibrium constant becomes reciprocal of the actual reaction

and when its coefficients are halved it gets 1/2 power on it

so, for the reaction shown below

the equilibrium constant will be (1/k)^(1/2)= 1/√278