7 years ago a father was 7 times as old as his son, 3 years hence he w

1.	7 years ago a father was 7 times as old as his son, 3 years hence he will be only 3 times to the age of his son. Their present ages are:1. 45, 122. 42, 123. 36, 74. 48, 15
Answer» Correct Answer - Option 2 : 42, 12 Given: 7 years ago father was 7 times as old as his son 3 years from now father will be 3 times to the age of his son Calculation: Let the present age of the son be x Age of the father 7 years ago = 7 × (x - 7) Age of the father 3 years from now = 3 × (x + 3) Also, Age of the father 3 years from now = 7 × (x - 7) + 10 7 × (x - 7) + 10 = 3 × (x - 3) ⇒ 7x - 49 + 10 = 3x - 9 ⇒ 4x = 48 ⇒ x = 12 Present age of the father = 3 × (x + 3) - 3 ⇒ 3 × 15 - 3 ⇒ 42 ∴ Present age of father and son is 42 and 12 years respectively.

7 years ago a father was 7 times as old as his son, 3 years hence he will be only 3 times to the age of his son. Their present ages are:1. 45, 122. 42, 123. 36, 74. 48, 15

Answer» Correct Answer - Option 2 : 42, 12

Given:

7 years ago father was 7 times as old as his son

3 years from now father will be 3 times to the age of his son

Calculation:

Let the present age of the son be x

Age of the father 7 years ago = 7 × (x - 7)

Age of the father 3 years from now = 3 × (x + 3)

Also, Age of the father 3 years from now = 7 × (x - 7) + 10

7 × (x - 7) + 10 = 3 × (x - 3)

⇒ 7x - 49 + 10 = 3x - 9

⇒ 4x = 48

⇒ x = 12

Present age of the father = 3 × (x + 3) - 3

⇒ 3 × 15 - 3

⇒ 42

∴ Present age of father and son is 42 and 12 years respectively.

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