75 ml of gas A effuses through a pin hole in 73 seconds the same volume of SO_(2) under indential conditions effuses in seconds. Calculate the molecular mass of A.

75 ml of gas A effuses through a pin hole in 73 seconds the same volum

1.	75 ml of gas A effuses through a pin hole in 73 seconds the same volume of SO_(2) under indential conditions effuses in seconds. Calculate the molecular mass of A.
Answer» Solution :`("EFFUSION rate of" CO_(2)) /("Effusion rate of A") = SQRT((M_(A))/(M_(CO_(2))))` `(50/115)/(50/146) = sqrt((M_(A))/(44)) , (1.27)^(2) = (M_(A))/(44)` `M_(A) = 71 therefore` Molecular MASS of A is 71 .