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7th and 19th terms of an A.P. are respectively 148 and 100. Which term of A.P. will be zero​

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Answer:

Let  a and d be the first TERM and the COMMON DIFFERENCE of the given AP RESPECTIVELY. Then,

a19=52⇒a+18d=52                    ...(1)

a38=148⇒a+37d=148                ...(2)

On subtracting (1) from (2), we get

19d=96⇒d=1996

Putting d=1996 in (1), we get

a=52−18×1996=19−740

Now, S56=256[2a+(56−1)d]

∴S56=28[193800]=5600

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