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8+16+24+.... +8n=4n(n+1) गणितीय अधिष्ठापन |
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Answer» \(8 + 16 + 24 + \,....+ 8n\) \(= 8(1 + 2 + 3 + ...+ n)\) \(= 8\frac {n(n+ 1)}{2}\) \(\left(\because 1 + 2 + 3 + ....+ n = \frac {n(n + 1)}{2}\right)\) \(= 4n(n+ 1)\) Hence proved. |
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