1.

8.96 L of Cl2 gas which is at STP is mixed with 100 mL of 5 M Ca(OH)2 which reacts as follows:2Ca(OH)2+2Cl2→Ca(OCl)2+CaCl2+2H2OFind the number of chlorine atoms present in Ca(OCl)2 that is formed.

Answer»

8.96 L of Cl2 gas which is at STP is mixed with 100 mL of 5 M Ca(OH)2 which reacts as follows:

2Ca(OH)2+2Cl2Ca(OCl)2+CaCl2+2H2O



Find the number of chlorine atoms present in Ca(OCl)2 that is formed.



Discussion

No Comment Found