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For the reaction, PCl3 (g) + Cl2 (g) = PCl5 (g) , ∆H = -x KJ If the ∆ Hf°PCl3 is -y KJ, what is ∆Hf°PCl5? |
Answer» For the reaction, <br>PCl3 (g) + Cl2 (g) = PCl5 (g) , ∆H = -x KJ <br>If the ∆ Hf°PCl3 is -y KJ, what is ∆Hf°PCl5? | |