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                                    For the reaction, PCl3 (g) + Cl2 (g) = PCl5 (g) , ∆H = -x KJ If the ∆ Hf°PCl3 is -y KJ, what is ∆Hf°PCl5? | 
                            
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Answer» For the reaction,  PCl3 (g) + Cl2 (g) = PCl5 (g) , ∆H = -x KJ If the ∆ Hf°PCl3 is -y KJ, what is ∆Hf°PCl5?  | 
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