InterviewSolution
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InterviewSolution
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8 g of HBr is added in 100 g of `H_(2)`The freezing point will be `(K_(f) = 1.86, H=1, br = 80 )`A. `-0.75^(@)C`B. `0^(@) `C. `-3.67 ^(@) C`D. `-7.6 ^(@) C ` |
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Answer» Correct Answer - C `Delta T_(f) = iK_(f) xx (W_(2) xx 1000)/(M_(2) xx W_(1)) = 2 xx 1.86 xx (8 xx 100)/(81 xx 100)=3.67^(@)` `T_(f) = T^(@) - Delta T_(f) = -3.67^(@) C` |
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