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`8 g` of sulphur are burnt to form `SO_(2)`, which is oxidised by `Cl_(2)` water. The solution is treated with `BaCl_(2)` solution. The amount of `BaSO_(4)` precipitated is:A. 1.0 moleB. 0.5 moleC. 0.75 moleD. 0.25 mole |
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Answer» Correct Answer - D `S overset (O_2)rarr SO_2 overset (Cl_2)rarr SO_4^(-) overset (BaCl_2)rarr BaSO_4` One mole of `S` will give `1` mole of `BaSO_4` Mole of `BaSO_4` formed = moles of sulphur `= (8)/(32) = (1)/(4) = 0.25`. |
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