8 gm H_2 and 256 gm HI in 4 L flask calculate this active mass. (H = 1 g "mol"^(-1), I = 127 g "mol"^(-1))

8 gm H_2 and 256 gm HI in 4 L flask calculate this active mass. (H = 1

1.	8 gm H_2 and 256 gm HI in 4 L flask calculate this active mass. (H = 1 g "mol"^(-1), I = 127 g "mol"^(-1))
Answer» SOLUTION :1 MOL `L^(-1) H_2`, 0.5 mol `L^(-1)` HI