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8·lf 3p? = 5p + 2 and 3q2-5q + 2 where p # q, pq is equal to |
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Answer» Given roots are 3p-2q,3q-2phence sum of roots=p+qproduct of roots=13pq-6(p^2+q^2)so eqn is x^2+(p+q)x+13pq-6(p^2+q^2)...................(1)also given 3p^2=5p+2..........(2) and 3q^2=5q+2..............(3)by subtracting 3 from 2 we get p+q=5/3By adding 2 and 3 we get p^2+q^2=37/9so pq=(p+q)^2-(p^2+q^²)=-6/9 = -2/3 |
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