1.

.8.Solve the quadratic equation:2x+1,

Answer»

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Let 4x-3/2x+1 = yand 2x+1/4x-3 =1/y since its reciprocalso, y-10(1/y) = 3y-10/y = 3y²-10 = 3yy² - 3y - 10 = 0y² - 5y +2y - 10 = 0y(y-5) + 2(y-5) = 0(y-5)(y+2) = 0y = 5 and y = -2

For y = 5(4x-3)/(2x + 1) = 54x - 3 = 10x + 56x = - 8x = - 4/3

For y = - 2(4x-3)/(2x + 1) = - 24x - 3 = - 4x - 28x = 1x = 1/8



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