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8.stezth3LE(I :1knesth blab le.) F ę¸le gF gellahe II |
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Answer» AD= AE = lengths of tangents from point A to the ex-circle of triangle ABC.BF = BD = lengths tangents from B onto the excircle.CE = CF = lengths of tangents from C onto the excircle. AD = AB + BD = AB + BF AE = AD = AC + CE = AC + CFAD+ AE = 2 AD= AB + BF+ FC + CA = perimeter of triangle ABC So perimeter = 2 * 5 cm = 10 cm |
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