8 taps of the same size fill a tank in 27 minutes. If two taps go out

1.	8 taps of the same size fill a tank in 27 minutes. If two taps go out of order, how long would the remaining taps take to fill the tank?
Answer» More the number of taps, lesser the time required to fill a tank. So, it is an inverse proportion. Let the required time be x minutes. ⇒ 8 × 27 = 6 × x ⇒ x = \(\frac{8\,\times\,27}{6}=\) 36 minutes

8 taps of the same size fill a tank in 27 minutes. If two taps go out of order, how long would the remaining taps take to fill the tank?

Answer»

More the number of taps, lesser the time required to fill a tank. So, it is an inverse proportion.

Let the required time be x minutes.

⇒ 8 × 27 = 6 × x

⇒ x = \(\frac{8\,\times\,27}{6}=\) 36 minutes