InterviewSolution
Saved Bookmarks
| 1. |
8. The dimensions of a cell phone are 544inches by 2.64 inches by 0.27 inches. Insquare inches, what is the surface area of thephone? |
|
Answer» Surface area of cuboidal phone= 2(lb+bh+hl)=2((5.44*2.64)+(2.64*0.27)+(0.27*5.44))=2(14.36+0.71+1.47)=2*16.54 =33.08 sq. inches |
|