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80% of the radioactive nuclei present in a sample is found to remain undecayed after one day. The percentage of undecayed nuclei left after two days will beA. 64B. 20C. 46D. 80 |
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Answer» Correct Answer - a `lambda = (2.303)/(t) log ((N_(0))/(N))` `= (2.303)/(1) log ((100)/(80))` `lambda = (2.303)/(2) log ((100)/(N))` `(2.303)/(1) log ((100)/(80)) = (2.303)/(2) log ((100)/(N))` `((5)/(4))^(2) = (100)/(N)` `N = 64` |
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