1.

81161. Insert 6 G. Ms betweenand-527

Answer»

the terms would be8/27, (8/27)r, (8/27)r^2, (8/27)r^3, (8/27)r^4, (8/27)r^5, (8/27)r^6 , -81/6

(8/27)r / (8/27) = (-81/16) / ((8/27)r^5)

r^7 = (-81/16)(27/8)r^7 = (-3)^7 / 2^7r = -3/2

Now terms are (8/27)*(-3/2) = - 4/9(8/27)*(9/4)= 2/3(8/27)*(-27/8) = - 1(8/27)*(81/16) = 3/2(8/27)*(-243/32) = - 9/4(8/27)*(728/64) = 27/8



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