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Answer»

We need to find H.C.F of 403, 434 and 465 to find themaximum capacity of a container that can measure the diesel of the three containersexact number of times.

Let's find the prime factors of 403, 434 and 465.

403=13×31

434=2×7×31

465=3×5×31

31 is the only common prime factor of 403, 434 and 465. Therefore, 31 is the H.C.F of 403, 434 and 465.



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