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831 The position x (t) of a particle at any time (t) is given byx (t) = 4t^3 - 3 t2 + 2The acceleration and velocity of the particle will be zero attime t = 2 s are respectively(A) 12 m s-2 and 25 m s-1 (B) 16 m s-2 and 22 m s-1(C) 42 m s-2 and 36 m s-1 (D) 48 m s-2 and 36 m s-1(A.I.I.M.S. 2009) |
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Answer» ANSWER Position of the particle x=2t −t 3
dt dx
=4t−3t 2
Acceleration a= dt dv
=4−6t So, a( at t=2 s)=4−6×2=−8 m/s 2
Since, acceleration is depending on the time. SO, acceleration is not CONSTANT. |
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