870 cc of moist hydrogen measured at 9 degree celsius and 659 mm pressure.find the volume of dry hydrogen at N.T.P .the vapur pressure of water at 9 degree celsius is 9 mm

870 cc of moist hydrogen measured at 9 degree celsius and 659 mm press

1.	870 cc of moist hydrogen measured at 9 degree celsius and 659 mm pressure.find the volume of dry hydrogen at N.T.P .the vapur pressure of water at 9 degree celsius is 9 mm
Answer» Explanation: Given: 870cc of moist hydrogen measured at 90C and 659 mm pressure. To FIND: the volume of dry hydrogen at NTP Solution: By Using Dalton's Law; Ptotal = Pdry hydrogen + Pwater 659 = Pdry hydrogen + 9 Therefore, Pdry hydrogen = 650 mm Let P1, V1 be the pressure and volume of the dry hydrogen respectively at temperatitr T1. Let P2, V2 be the pressure and volume of the dry hydrogen respectively at temperatitr T2. Let us calculate the volume V2 of dry hydrogen at NTP. Using combined gas equation, we get, begin mathsize 11px style fraction numerator straight P subscript 1 straight V subscript 1 over denominator straight T subscript 1 end fraction space equals space fraction numerator straight P subscript 2 straight V subscript 2 over denominator straight T subscript 2 end fraction fraction numerator 650 space cross times space 870 over denominator 282 end fraction space equals space fraction numerator 760 space cross times space straight V subscript 2 over denominator 273 end fraction rightwards double arrow space straight V subscript 2 space equals space 720.33 space cc end style

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870 cc of moist hydrogen measured at 9 degree celsius and 659 mm pressure.find the volume of dry hydrogen at N.T.P .the vapur pressure of water at 9 degree celsius is 9 mm​

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870 cc of moist hydrogen measured at 9 degree celsius and 659 mm pressure.find the volume of dry hydrogen at N.T.P .the vapur pressure of water at 9 degree celsius is 9 mm