InterviewSolution
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InterviewSolution
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88D 9 G-R= g o .‘-a124 frnd FanB )”——b‘_— . o5 Q\r—_——bl‘ 2 o |
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Answer» SinA= a/b we know {sinA}^2 +{cos A}^2=1or, cosA={1-(sinA)^2}^(1÷2)={1- (a/b)^2}^(1÷2)so, tanA=sinA÷cosA=(a/b)÷√{1-(a/b)^2}simplifying we get tanA= a÷√(b^2-a^2) |
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