

InterviewSolution
Saved Bookmarks
1. |
`9.65` amp of current was passed for one hour through Daniel cell. The loss of mass of zinc anode isA. 11.77 g , 11.43 gB. 11.43 g , 11.77 gC. 23.54 g , 22.84 gD. 22.86 g 23.54 g |
Answer» Correct Answer - A `Q = 9.65 xx 60 xx 60 = 34740` C At anode ` : Zn to Zn^(2+) + 2e^(-)` Loss mass of Zn by `2 xx 96500 C = 65.4` g `therefore ` Loss in mass by 34740 C = 11.77 g At cathode `: Cu^(2+) + 2e^(-) to Cu` . Gain in mass of Cu by `2 xx 96500 C = 63.5`g `therefore` Gain in mass of Cu by 34740 C = `(63.5)/(2 xx 96500) xx 3474 = 11 .43`g |
|