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InterviewSolution
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`9*65D` C of electric current is passed through fused anhydrous magnesium chloride. The magnesium metal thus, obtained is completely converted into a grignard reagents. What is the number of moles of grignard reagent obtained? |
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Answer» `MgCl_(2)overset((aq))(to)MgCl^(2)+(aq)+2Cl^(-)(aq)` `Mg^(2+)(aq)+underset((2xx96500C))(2e)^(-)toMg(s)` (At cathode) `2xx29500C` of charge deposite MG metal =1mol `9*65C` of charge deposite Mg metal `=((1mol))/((2xx96500C))xx(9*65C)=5xx10^(-5)mol` `R-X+underset(1mol)(Mg)("Anhyd. ether")toR-underset(1mol)(MG)-X` `therefore` No of moles of grignard reagent obtained `=5xx10^(-5)`mol. |
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