Saved Bookmarks
| 1. |
9. A body moving with initial velocity \( 83 m / s \) moved under constant retardation of \( 3 m / s ^{2} \). Find its velocity after \( 2 sec \). Time after which it will stop and the aíctance it will travel before coming to rest. |
|
Answer» As per question, u = 83m/s a = -3m/s2 t = 2 s v = ? v = u + at v = 83 + (-3) x 2 v = 83 - 6 = 77m/s Ans..... To find the time after which it stops i.e. v becomes 0. again v = u + at 0 = 83 - 3 x t t = 83/3 = 27.66s Ans.... To find the distance travelled before coming to rest, v2 = u2 + 2ax ( also x = ut + 1/2 at2 can be used) 02 = 832 + 2(-3) x x = - 832/-6 = 1148.16m Ans...... Given initial velocity, u = 83 m/s a = 3 m/s2 t = 2 sec v = u + at v = 83 + 3 x 2 after 2 sec velocity v = 89 m/s. |
|