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9. A hollow cylindrical tube open at both cnds is made of iron 3 cm thick. If the external diameter be 56 cmand the length of the tube be 182 cm, find the number of cubic em in it. |
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Answer» Given, thickness of iron =3cm external diameter = 56cm Length of tube = 182cmWe know, volume of hollow cylinder = πh(R²−r²)∴ internal diameter = external diameter−2×thickness of iron= 56−2×3 = 56−6 = 50cm => Outer radius(R) = 56÷2 = 28cm inner radius(r) = 50÷2 = 25cm∴ Volume of hollow cylinder = πh(R²−r²) = 3.14×182(28²−25²) = 3.14×82×159 = 90865.32cm³ Answer |
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