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9 added to the product of two consecutive multiples of 6 gives 729. What are the numbers? |
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Answer» Let the two consecutive multiples of 6 be x, x + 6 x, x + 6 x(x + 6) + 9 = 729 x2 + 6x + 9 = 729 x2 + 6x = 720 x2 + 6x – 720 = O x + 6x = 720 (x + 3)2 = 720 + 9 (x + 3)2 = 729 x + 3 = ± 27 x = 24, – 30 The numbers are 24, – 30 |
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