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9. Find the measure of the side of a rhombus if its diagonals35 cm and 28 cm. |
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Answer» Let ABCD be a rhombus. with O as intersection of diagonals.And we know that diagonal bisect each other>OA=1/2AD=35/2=17.5>OB=1/2BC=28/2=14By Pythagoras TheoremAB^2=OA^2+OB^2AB^2=17.5^2+14^2AB^2=502.25AB=√502.25AB=22.14cm |
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