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9. Find the smallest number which when divided by35, 56 and 91 leaves remainder 7 in each case. |
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Answer» smallest number=7 The smallest number which when divided by 35, 56 and 91 = LCM of 35, 56 and 9135 = 5 x 756 = 2 x 2 x 2 x 791 = 7 x 13LCM = 7 x 5 x 2 x 2 x 2 x 13 = 3640The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.2) |
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