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9. If both the roots of \( k\left(6 x^{2}+3\right)+r x+2 x^{2}-1=0 \) and \( 6 k\left(2 x^{2}+1\right)+p x+4 x^{2}-2=0 \) are common, then \( 2 r-p \) is equal to(1) \( -1 \)(2) 0

Answer»

If you solve and make the two equations inthe form of ax2+bx+c, thrn you will see that the 2nd eqn. is double of 1st eqn.

So, 2r = p

So, 2r-p=2r-2r= 0

Hope It Helped You




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